Local fans have another reason to celebrate as Cincinnati Bengals wide receiver Tee Higgins was recognized as the AFC Offensive Player of the Week for the second consecutive week. Higgins earned the accolade for his standout effort in the Bengals’ 43‑36 overtime victory against the Tennessee Titans on Sunday.
Performance that stood out
Against the Titans, Higgins hauled in 10 receptions, racking up 155 receiving yards and scoring two touchdowns. His 155 yards topped all NFL players for Week 8, underscoring his role as a key offensive weapon for Cincinnati.
Back‑to‑back honors for the Bengals
This marks the first time in Higgins’ career that he has received the AFC Offensive Player of the Week award. The Bengals have now secured the honor for two weeks in a row, with quarterback Joe Burrow earning the award for Week 7.
What the award means for Cincinnati
The recognition highlights the Bengals’ offensive momentum as they chase a playoff berth. Higgins’ ability to create big plays downfield complements Burrow’s passing proficiency, giving the team a balanced attack that can challenge any opponent.
Looking ahead
With the season entering its critical stretch, the Bengals will aim to build on this success. Higgins’ performance not only boosts his personal profile but also energizes the fan base, reinforcing Cincinnati’s reputation as a city that supports its athletes and celebrates their achievements.
Fans can catch the next Bengals game on local television or stream it online, and they are encouraged to attend upcoming home games at Paycor Stadium to witness more standout performances from Higgins and the rest of the squad.
Original reporting: WHIO-TV Dayton (local) — read the source article.
